NbIrTe$_{4}$ Structure: ABC4_oP24_31_2a_2a_8a-001

Picture of Structure; Click for Big Picture
Prototype IrNbTe$_{4}$
AFLOW prototype label ABC4_oP24_31_2a_2a_8a-001
ICSD 73690
CCDC 1634457
Pearson symbol oP24
Space group number 31
Space group symbol $Pmn2_1$
AFLOW prototype command aflow --proto=ABC4_oP24_31_2a_2a_8a-001
--params=$a, \allowbreak b/a, \allowbreak c/a, \allowbreak y_{1}, \allowbreak z_{1}, \allowbreak y_{2}, \allowbreak z_{2}, \allowbreak y_{3}, \allowbreak z_{3}, \allowbreak y_{4}, \allowbreak z_{4}, \allowbreak y_{5}, \allowbreak z_{5}, \allowbreak y_{6}, \allowbreak z_{6}, \allowbreak y_{7}, \allowbreak z_{7}, \allowbreak y_{8}, \allowbreak z_{8}, \allowbreak y_{9}, \allowbreak z_{9}, \allowbreak y_{10}, \allowbreak z_{10}, \allowbreak y_{11}, \allowbreak z_{11}, \allowbreak y_{12}, \allowbreak z_{12}$

Other compounds with this structure

NbOsTe$_{4}$,  TaIrTe$_{4}$,  TaOsTe$_{4}$,  TaRhTe$_{4}$,  TaRuTe$_{4}$


  • Space group $Pmn2_{1}$ #31 allows an arbitrary placement of the origin of the $z$-axis. Here we set $z_{1} = 0$ for the first iridium Wyckoff position.

\[ \begin{array}{ccc} \mathbf{a_{1}}&=&a \,\mathbf{\hat{x}}\\\mathbf{a_{2}}&=&b \,\mathbf{\hat{y}}\\\mathbf{a_{3}}&=&c \,\mathbf{\hat{z}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $y_{1} \, \mathbf{a}_{2}+z_{1} \, \mathbf{a}_{3}$ = $b y_{1} \,\mathbf{\hat{y}}+c z_{1} \,\mathbf{\hat{z}}$ (2a) Ir I
$\mathbf{B_{2}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{1} \, \mathbf{a}_{2}+\left(z_{1} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{1} \,\mathbf{\hat{y}}+c \left(z_{1} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Ir I
$\mathbf{B_{3}}$ = $y_{2} \, \mathbf{a}_{2}+z_{2} \, \mathbf{a}_{3}$ = $b y_{2} \,\mathbf{\hat{y}}+c z_{2} \,\mathbf{\hat{z}}$ (2a) Ir II
$\mathbf{B_{4}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{2} \, \mathbf{a}_{2}+\left(z_{2} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{2} \,\mathbf{\hat{y}}+c \left(z_{2} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Ir II
$\mathbf{B_{5}}$ = $y_{3} \, \mathbf{a}_{2}+z_{3} \, \mathbf{a}_{3}$ = $b y_{3} \,\mathbf{\hat{y}}+c z_{3} \,\mathbf{\hat{z}}$ (2a) Nb I
$\mathbf{B_{6}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{3} \, \mathbf{a}_{2}+\left(z_{3} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{3} \,\mathbf{\hat{y}}+c \left(z_{3} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Nb I
$\mathbf{B_{7}}$ = $y_{4} \, \mathbf{a}_{2}+z_{4} \, \mathbf{a}_{3}$ = $b y_{4} \,\mathbf{\hat{y}}+c z_{4} \,\mathbf{\hat{z}}$ (2a) Nb II
$\mathbf{B_{8}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{4} \, \mathbf{a}_{2}+\left(z_{4} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{4} \,\mathbf{\hat{y}}+c \left(z_{4} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Nb II
$\mathbf{B_{9}}$ = $y_{5} \, \mathbf{a}_{2}+z_{5} \, \mathbf{a}_{3}$ = $b y_{5} \,\mathbf{\hat{y}}+c z_{5} \,\mathbf{\hat{z}}$ (2a) Te I
$\mathbf{B_{10}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{5} \, \mathbf{a}_{2}+\left(z_{5} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{5} \,\mathbf{\hat{y}}+c \left(z_{5} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te I
$\mathbf{B_{11}}$ = $y_{6} \, \mathbf{a}_{2}+z_{6} \, \mathbf{a}_{3}$ = $b y_{6} \,\mathbf{\hat{y}}+c z_{6} \,\mathbf{\hat{z}}$ (2a) Te II
$\mathbf{B_{12}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{6} \, \mathbf{a}_{2}+\left(z_{6} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{6} \,\mathbf{\hat{y}}+c \left(z_{6} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te II
$\mathbf{B_{13}}$ = $y_{7} \, \mathbf{a}_{2}+z_{7} \, \mathbf{a}_{3}$ = $b y_{7} \,\mathbf{\hat{y}}+c z_{7} \,\mathbf{\hat{z}}$ (2a) Te III
$\mathbf{B_{14}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{7} \, \mathbf{a}_{2}+\left(z_{7} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{7} \,\mathbf{\hat{y}}+c \left(z_{7} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te III
$\mathbf{B_{15}}$ = $y_{8} \, \mathbf{a}_{2}+z_{8} \, \mathbf{a}_{3}$ = $b y_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (2a) Te IV
$\mathbf{B_{16}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{8} \, \mathbf{a}_{2}+\left(z_{8} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{8} \,\mathbf{\hat{y}}+c \left(z_{8} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te IV
$\mathbf{B_{17}}$ = $y_{9} \, \mathbf{a}_{2}+z_{9} \, \mathbf{a}_{3}$ = $b y_{9} \,\mathbf{\hat{y}}+c z_{9} \,\mathbf{\hat{z}}$ (2a) Te V
$\mathbf{B_{18}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{9} \, \mathbf{a}_{2}+\left(z_{9} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{9} \,\mathbf{\hat{y}}+c \left(z_{9} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te V
$\mathbf{B_{19}}$ = $y_{10} \, \mathbf{a}_{2}+z_{10} \, \mathbf{a}_{3}$ = $b y_{10} \,\mathbf{\hat{y}}+c z_{10} \,\mathbf{\hat{z}}$ (2a) Te VI
$\mathbf{B_{20}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{10} \, \mathbf{a}_{2}+\left(z_{10} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{10} \,\mathbf{\hat{y}}+c \left(z_{10} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te VI
$\mathbf{B_{21}}$ = $y_{11} \, \mathbf{a}_{2}+z_{11} \, \mathbf{a}_{3}$ = $b y_{11} \,\mathbf{\hat{y}}+c z_{11} \,\mathbf{\hat{z}}$ (2a) Te VII
$\mathbf{B_{22}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{11} \, \mathbf{a}_{2}+\left(z_{11} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{11} \,\mathbf{\hat{y}}+c \left(z_{11} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te VII
$\mathbf{B_{23}}$ = $y_{12} \, \mathbf{a}_{2}+z_{12} \, \mathbf{a}_{3}$ = $b y_{12} \,\mathbf{\hat{y}}+c z_{12} \,\mathbf{\hat{z}}$ (2a) Te VIII
$\mathbf{B_{24}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- y_{12} \, \mathbf{a}_{2}+\left(z_{12} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $\frac{1}{2}a \,\mathbf{\hat{x}}- b y_{12} \,\mathbf{\hat{y}}+c \left(z_{12} + \frac{1}{2}\right) \,\mathbf{\hat{z}}$ (2a) Te VIII

References

  • A. Mar and J. A. Ibers, Synthesis and physical properties of the new layered ternary tellurides MIrTe$_{4}$ (M = Nb, Ta), and the structure of NbIrTe$_{4}$, J. Solid State Chem. 97, 366–376 (1992), doi:10.1016/0022-4596(92)90045-W.

Found in

  • A. Mar, S. Jobic, and J. A. Ibers, Metal-metal vs tellurium-tellurium bonding in WTe$_{2}$ and its ternary variants TaIrTe$_{4}$ and NbIrTe$_{4}$, J. Am. Chem. Soc. 114, 8963–8971 (1992), doi:10.1021/ja00049a029.

First cited in

  • N. Anderson, M. J. Mehl, H. Eckert, S. Divilov, X. Campilongo, S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 5. Submitted to Computational Materials Science (2026).

Geometry files


Prototype Generator

aflow --proto=ABC4_oP24_31_2a_2a_8a --params=$a,b/a,c/a,y_{1},z_{1},y_{2},z_{2},y_{3},z_{3},y_{4},z_{4},y_{5},z_{5},y_{6},z_{6},y_{7},z_{7},y_{8},z_{8},y_{9},z_{9},y_{10},z_{10},y_{11},z_{11},y_{12},z_{12}$

Species:

Running:

Output: