LaTi$_{3}$Bi$_{4}$ Structure: A4BC3_oF64_69_gho_g_gl-001

Picture of Structure; Click for Big Picture
Prototype Bi$_{4}$LaTi$_{3}$
AFLOW prototype label A4BC3_oF64_69_gho_g_gl-001
ICSD 119550
CCDC 2335975
Pearson symbol oF64
Space group number 69
Space group symbol $Fmmm$
AFLOW prototype command aflow --proto=A4BC3_oF64_69_gho_g_gl-001
--params=$a, \allowbreak b/a, \allowbreak c/a, \allowbreak x_{1}, \allowbreak x_{2}, \allowbreak x_{3}, \allowbreak y_{4}, \allowbreak x_{5}, \allowbreak x_{6}, \allowbreak y_{6}$

Other compounds with this structure

CaTi$_{3}$Bi$_{4}$,  CaV$_{3}$Sb$_{4}$,  CeTi$_{3}$Bi$_{4}$,  DyTi$_{3}$Bi$_{4}$,  ErTi$_{3}$Bi$_{4}$,  EuTi$_{3}$Bi$_{4}$,  GdTi$_{3}$Bi$_{4}$,  HoTi$_{3}$Bi$_{4}$,  LuTi$_{3}$Bi$_{4}$,  NdTi$_{3}$Bi$_{4}$,  PmTi$_{3}$Bi$_{4}$,  PrTi$_{3}$Bi$_{4}$,  SmTi$_{3}$Bi$_{4}$,  TbTi$_{3}$Bi$_{4}$,  TmTi$_{3}$Bi$_{4}$,  YbTi$_{3}$Bi$_{4}$,  Nd(Sb,  Sn)$_{3}$Bi$_{4}$


  • In orthorhombic systems the AFLOW prototype label standard favors orientations of where most of the free atomic parameters are along the x-axis. Thus we have rotated the published structure so that coordinates (x,y,z) $\rightarrow$ (z,y,-x), with a similar change for the lattice parameters.
  • The ICSD lists Nd(Sb,Sn)$_{3}$Bi$_{4}$ as the prototype for this structure, but we prefer to use a fully ordered structure.

\[ \begin{array}{ccc} \mathbf{a_{1}}&=&\frac{1}{2}b \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}\\\mathbf{a_{2}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}c \,\mathbf{\hat{z}}\\\mathbf{a_{3}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}b \,\mathbf{\hat{y}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $- x_{1} \, \mathbf{a}_{1}+x_{1} \, \mathbf{a}_{2}+x_{1} \, \mathbf{a}_{3}$ = $a x_{1} \,\mathbf{\hat{x}}$ (8g) Bi I
$\mathbf{B_{2}}$ = $x_{1} \, \mathbf{a}_{1}- x_{1} \, \mathbf{a}_{2}- x_{1} \, \mathbf{a}_{3}$ = $- a x_{1} \,\mathbf{\hat{x}}$ (8g) Bi I
$\mathbf{B_{3}}$ = $- x_{2} \, \mathbf{a}_{1}+x_{2} \, \mathbf{a}_{2}+x_{2} \, \mathbf{a}_{3}$ = $a x_{2} \,\mathbf{\hat{x}}$ (8g) La I
$\mathbf{B_{4}}$ = $x_{2} \, \mathbf{a}_{1}- x_{2} \, \mathbf{a}_{2}- x_{2} \, \mathbf{a}_{3}$ = $- a x_{2} \,\mathbf{\hat{x}}$ (8g) La I
$\mathbf{B_{5}}$ = $- x_{3} \, \mathbf{a}_{1}+x_{3} \, \mathbf{a}_{2}+x_{3} \, \mathbf{a}_{3}$ = $a x_{3} \,\mathbf{\hat{x}}$ (8g) Ti I
$\mathbf{B_{6}}$ = $x_{3} \, \mathbf{a}_{1}- x_{3} \, \mathbf{a}_{2}- x_{3} \, \mathbf{a}_{3}$ = $- a x_{3} \,\mathbf{\hat{x}}$ (8g) Ti I
$\mathbf{B_{7}}$ = $y_{4} \, \mathbf{a}_{1}- y_{4} \, \mathbf{a}_{2}+y_{4} \, \mathbf{a}_{3}$ = $b y_{4} \,\mathbf{\hat{y}}$ (8h) Bi II
$\mathbf{B_{8}}$ = $- y_{4} \, \mathbf{a}_{1}+y_{4} \, \mathbf{a}_{2}- y_{4} \, \mathbf{a}_{3}$ = $- b y_{4} \,\mathbf{\hat{y}}$ (8h) Bi II
$\mathbf{B_{9}}$ = $- \left(x_{5} - \frac{1}{2}\right) \, \mathbf{a}_{1}+x_{5} \, \mathbf{a}_{2}+x_{5} \, \mathbf{a}_{3}$ = $a x_{5} \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (16l) Ti II
$\mathbf{B_{10}}$ = $x_{5} \, \mathbf{a}_{1}- \left(x_{5} - \frac{1}{2}\right) \, \mathbf{a}_{2}- \left(x_{5} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a \left(x_{5} - \frac{1}{2}\right) \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (16l) Ti II
$\mathbf{B_{11}}$ = $\left(x_{5} + \frac{1}{2}\right) \, \mathbf{a}_{1}- x_{5} \, \mathbf{a}_{2}- x_{5} \, \mathbf{a}_{3}$ = $- a x_{5} \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (16l) Ti II
$\mathbf{B_{12}}$ = $- x_{5} \, \mathbf{a}_{1}+\left(x_{5} + \frac{1}{2}\right) \, \mathbf{a}_{2}+\left(x_{5} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a \left(x_{5} + \frac{1}{2}\right) \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (16l) Ti II
$\mathbf{B_{13}}$ = $- \left(x_{6} - y_{6}\right) \, \mathbf{a}_{1}+\left(x_{6} - y_{6}\right) \, \mathbf{a}_{2}+\left(x_{6} + y_{6}\right) \, \mathbf{a}_{3}$ = $a x_{6} \,\mathbf{\hat{x}}+b y_{6} \,\mathbf{\hat{y}}$ (16o) Bi III
$\mathbf{B_{14}}$ = $\left(x_{6} - y_{6}\right) \, \mathbf{a}_{1}- \left(x_{6} - y_{6}\right) \, \mathbf{a}_{2}- \left(x_{6} + y_{6}\right) \, \mathbf{a}_{3}$ = $- a x_{6} \,\mathbf{\hat{x}}- b y_{6} \,\mathbf{\hat{y}}$ (16o) Bi III
$\mathbf{B_{15}}$ = $\left(x_{6} + y_{6}\right) \, \mathbf{a}_{1}- \left(x_{6} + y_{6}\right) \, \mathbf{a}_{2}- \left(x_{6} - y_{6}\right) \, \mathbf{a}_{3}$ = $- a x_{6} \,\mathbf{\hat{x}}+b y_{6} \,\mathbf{\hat{y}}$ (16o) Bi III
$\mathbf{B_{16}}$ = $- \left(x_{6} + y_{6}\right) \, \mathbf{a}_{1}+\left(x_{6} + y_{6}\right) \, \mathbf{a}_{2}+\left(x_{6} - y_{6}\right) \, \mathbf{a}_{3}$ = $a x_{6} \,\mathbf{\hat{x}}- b y_{6} \,\mathbf{\hat{y}}$ (16o) Bi III

References

  • B. R. Ortiz, H. Miao, D. S. Parker, F. Yang, G. D. Samolyuk, E. M. Clements, A. Rajapitamahuni, T. Yilmaz, E. Vescovo, J. Yan, A. F. May, and M. A. McGuire, Evolution of Highly Anisotropic Magnetism in the Titanium-Based Kagome Metals LnTi$_{3}$Bi$_{4}$ (Ln: La···Gd$^{3+}$, Eu$^{2+}$, Yb$^{2+}$), Chem. of Mater. 35, 9756–9773 (2023), doi:10.1021/acs.chemmater.3c02289.

Found in

  • B. R. Ortiz, H. Zhang, K. Górnicka, D. S. Parker, G. D. Samolyuk, F. Yang, H. Miao, Q. Lu, R. G. Moore, A. F. May, and M. A. McGuire, Intricate Magnetic Landscape in Antiferromagnetic Kagome Metal TbTi$_{3}$Bi$_{4}$ and Interplay with Ln$_{2-x}$Ti$_{6+x}$Bi$_{9}$ (Ln: Tb–Lu) Shurikagome Metals, Chem. Mater. 36, 8002–8014 (2024).

First cited in

  • N. Anderson, M. J. Mehl, H. Eckert, S. Divilov, X. Campilongo, S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 5. Submitted to Computational Materials Science (2026).

Geometry files


Prototype Generator

aflow --proto=A4BC3_oF64_69_gho_g_gl --params=$a,b/a,c/a,x_{1},x_{2},x_{3},y_{4},x_{5},x_{6},y_{6}$

Species:

Running:

Output: