Encyclopedia of Crystallographic Prototypes

AFLOW Prototype: A6B5_oI44_71_egkl_fghl-001

If you are using this page, please cite:
H. Eckert, S. Divilov, M. J. Mehl, D. Hicks, A. C. Zettel, M. Esters. X. Campilongo and S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 4. Submitted to Computational Materials Science.

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https://aflow.org/p/Q45R
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Nb$_{6}$Sn$_{5}$ Structure: A6B5_oI44_71_egkl_fghl-001

Picture of Structure; Click for Big Picture
Prototype Nb$_{6}$Sn$_{5}$
AFLOW prototype label A6B5_oI44_71_egkl_fghl-001
ICSD 105232
Pearson symbol oI44
Space group number 71
Space group symbol $Immm$
AFLOW prototype command aflow --proto=A6B5_oI44_71_egkl_fghl-001
--params=$a, \allowbreak b/a, \allowbreak c/a, \allowbreak x_{1}, \allowbreak x_{2}, \allowbreak y_{3}, \allowbreak y_{4}, \allowbreak y_{5}, \allowbreak y_{7}, \allowbreak z_{7}, \allowbreak y_{8}, \allowbreak z_{8}$

Other compounds with this structure

Ti$_{6}$Sn$_{5}$


  • (Ogren, 1965) state that what we have labeled the Sn-II (4g) site is only occupied 92% of the time.
  • (Villars, 2018) and others use Ti$_{6}$Sn$_{5}$ as the prototype for this structure. We follow (Pearson, 1967) and use Nb$_{6}$Sn$_{5}$ as the prototype.

\[ \begin{array}{ccc} \mathbf{a_{1}}&=&- \frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}b \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}\\\mathbf{a_{2}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{1}{2}b \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}\\\mathbf{a_{3}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}+\frac{1}{2}b \,\mathbf{\hat{y}}- \frac{1}{2}c \,\mathbf{\hat{z}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $x_{1} \, \mathbf{a}_{2}+x_{1} \, \mathbf{a}_{3}$ = $a x_{1} \,\mathbf{\hat{x}}$ (4e) Nb I
$\mathbf{B_{2}}$ = $- x_{1} \, \mathbf{a}_{2}- x_{1} \, \mathbf{a}_{3}$ = $- a x_{1} \,\mathbf{\hat{x}}$ (4e) Nb I
$\mathbf{B_{3}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+x_{2} \, \mathbf{a}_{2}+\left(x_{2} + \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $a x_{2} \,\mathbf{\hat{x}}+\frac{1}{2}b \,\mathbf{\hat{y}}$ (4f) Sn I
$\mathbf{B_{4}}$ = $\frac{1}{2} \, \mathbf{a}_{1}- x_{2} \, \mathbf{a}_{2}- \left(x_{2} - \frac{1}{2}\right) \, \mathbf{a}_{3}$ = $- a x_{2} \,\mathbf{\hat{x}}+\frac{1}{2}b \,\mathbf{\hat{y}}$ (4f) Sn I
$\mathbf{B_{5}}$ = $y_{3} \, \mathbf{a}_{1}+y_{3} \, \mathbf{a}_{3}$ = $b y_{3} \,\mathbf{\hat{y}}$ (4g) Nb II
$\mathbf{B_{6}}$ = $- y_{3} \, \mathbf{a}_{1}- y_{3} \, \mathbf{a}_{3}$ = $- b y_{3} \,\mathbf{\hat{y}}$ (4g) Nb II
$\mathbf{B_{7}}$ = $y_{4} \, \mathbf{a}_{1}+y_{4} \, \mathbf{a}_{3}$ = $b y_{4} \,\mathbf{\hat{y}}$ (4g) Sn II
$\mathbf{B_{8}}$ = $- y_{4} \, \mathbf{a}_{1}- y_{4} \, \mathbf{a}_{3}$ = $- b y_{4} \,\mathbf{\hat{y}}$ (4g) Sn II
$\mathbf{B_{9}}$ = $\left(y_{5} + \frac{1}{2}\right) \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}+y_{5} \, \mathbf{a}_{3}$ = $b y_{5} \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (4h) Sn III
$\mathbf{B_{10}}$ = $- \left(y_{5} - \frac{1}{2}\right) \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}- y_{5} \, \mathbf{a}_{3}$ = $- b y_{5} \,\mathbf{\hat{y}}+\frac{1}{2}c \,\mathbf{\hat{z}}$ (4h) Sn III
$\mathbf{B_{11}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (8k) Nb III
$\mathbf{B_{12}}$ = $\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}- \frac{1}{4}c \,\mathbf{\hat{z}}$ (8k) Nb III
$\mathbf{B_{13}}$ = $\frac{1}{2} \, \mathbf{a}_{2}$ = $\frac{1}{4}a \,\mathbf{\hat{x}}- \frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (8k) Nb III
$\mathbf{B_{14}}$ = $\frac{1}{2} \, \mathbf{a}_{1}$ = $- \frac{1}{4}a \,\mathbf{\hat{x}}+\frac{1}{4}b \,\mathbf{\hat{y}}+\frac{1}{4}c \,\mathbf{\hat{z}}$ (8k) Nb III
$\mathbf{B_{15}}$ = $\left(y_{7} + z_{7}\right) \, \mathbf{a}_{1}+z_{7} \, \mathbf{a}_{2}+y_{7} \, \mathbf{a}_{3}$ = $b y_{7} \,\mathbf{\hat{y}}+c z_{7} \,\mathbf{\hat{z}}$ (8l) Nb IV
$\mathbf{B_{16}}$ = $- \left(y_{7} - z_{7}\right) \, \mathbf{a}_{1}+z_{7} \, \mathbf{a}_{2}- y_{7} \, \mathbf{a}_{3}$ = $- b y_{7} \,\mathbf{\hat{y}}+c z_{7} \,\mathbf{\hat{z}}$ (8l) Nb IV
$\mathbf{B_{17}}$ = $\left(y_{7} - z_{7}\right) \, \mathbf{a}_{1}- z_{7} \, \mathbf{a}_{2}+y_{7} \, \mathbf{a}_{3}$ = $b y_{7} \,\mathbf{\hat{y}}- c z_{7} \,\mathbf{\hat{z}}$ (8l) Nb IV
$\mathbf{B_{18}}$ = $- \left(y_{7} + z_{7}\right) \, \mathbf{a}_{1}- z_{7} \, \mathbf{a}_{2}- y_{7} \, \mathbf{a}_{3}$ = $- b y_{7} \,\mathbf{\hat{y}}- c z_{7} \,\mathbf{\hat{z}}$ (8l) Nb IV
$\mathbf{B_{19}}$ = $\left(y_{8} + z_{8}\right) \, \mathbf{a}_{1}+z_{8} \, \mathbf{a}_{2}+y_{8} \, \mathbf{a}_{3}$ = $b y_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (8l) Sn IV
$\mathbf{B_{20}}$ = $- \left(y_{8} - z_{8}\right) \, \mathbf{a}_{1}+z_{8} \, \mathbf{a}_{2}- y_{8} \, \mathbf{a}_{3}$ = $- b y_{8} \,\mathbf{\hat{y}}+c z_{8} \,\mathbf{\hat{z}}$ (8l) Sn IV
$\mathbf{B_{21}}$ = $\left(y_{8} - z_{8}\right) \, \mathbf{a}_{1}- z_{8} \, \mathbf{a}_{2}+y_{8} \, \mathbf{a}_{3}$ = $b y_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (8l) Sn IV
$\mathbf{B_{22}}$ = $- \left(y_{8} + z_{8}\right) \, \mathbf{a}_{1}- z_{8} \, \mathbf{a}_{2}- y_{8} \, \mathbf{a}_{3}$ = $- b y_{8} \,\mathbf{\hat{y}}- c z_{8} \,\mathbf{\hat{z}}$ (8l) Sn IV

References

  • J. R. Ogren, T. G. Ellis, and J. F. Smith, The structure of Nb$_{6}$Sn$_{5}$, Acta Cryst. 18, 968–973 (1965), doi:10.1107/S0365110X6500230X.
  • W. B. Pearson, A Handbook of Lattice Spacings and Structures of Metals and Alloys, Volume 2, International Series of Monographs on Metal Physics and Physical Metallurgy, vol. 8 (Pergamon Press, Oxford, London, Edinburgh, New York, Toronto, Sydney, Paris, Braunschweig, 1967).

Found in

  • P. Villars, H. Okamoto, and K. Cenzual, eds., ASM Alloy Phase Diagram Database (ASM International, 2018), chap. Niobium-Tin Binary Phase Diagram (2009 Li M.). Copyright © 2006-2018 ASM International.

Prototype Generator

aflow --proto=A6B5_oI44_71_egkl_fghl --params=$a,b/a,c/a,x_{1},x_{2},y_{3},y_{4},y_{5},y_{7},z_{7},y_{8},z_{8}$

Species:

Running:

Output: