Encyclopedia of Crystallographic Prototypes

AFLOW Prototype: A4BC3D12_hR20_155_ad_b_e_2df-001

If you are using this page, please cite:
H. Eckert, S. Divilov, M. J. Mehl, D. Hicks, A. C. Zettel, M. Esters. X. Campilongo and S. Curtarolo, The AFLOW Library of Crystallographic Prototypes: Part 4. Submitted to Computational Materials Science.

Links to this page

https://aflow.org/p/1B5F
or https://aflow.org/p/A4BC3D12_hR20_155_ad_b_e_2df-001
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Huntite [CaMg$_{3}$(CO$_{3}$)$_{4}$] Structure: A4BC3D12_hR20_155_ad_b_e_2df-001

Picture of Structure; Click for Big Picture
Prototype C$_{3}$CaMg$_{3}$O$_{12}$
AFLOW prototype label A4BC3D12_hR20_155_ad_b_e_2df-001
Mineral name huntite
ICSD 201729
Pearson symbol hR20
Space group number 155
Space group symbol $R32$
AFLOW prototype command aflow --proto=A4BC3D12_hR20_155_ad_b_e_2df-001
--params=$a, \allowbreak c/a, \allowbreak y_{3}, \allowbreak y_{4}, \allowbreak y_{5}, \allowbreak y_{6}, \allowbreak x_{7}, \allowbreak y_{7}, \allowbreak z_{7}$

Other compounds with this structure

EuAl$_{3}$(BO$_{3}$)$_{4}$,  GdAl$_{3}$(BO$_{3}$)$_{4}$,  HoAl$_{3}$(BO$_{3}$)$_{4}$,  LaAl$_{3}$(BO$_{3}$)$_{4}$,  NdAl$_{3}$(BO$_{3}$)$_{4}$,  PrAl$_{3}$(BO$_{3}$)$_{4}$,  SmAl$_{3}$(BO$_{3}$)$_{4}$,  TbAl$_{3}$(BO$_{3}$)$_{4}$,  TmAl$_{3}$(BO$_{3}$)$_{4}$,  YAl$_{3}$(BO$_{3}$)$_{4}$,  YbAl$_{3}$(BO$_{3}$)$_{4}$


  • We have shifted the origin away from that used by (Dollase, 1986): the C-I atom is now on the (1a) Wyckoff position.
  • Hexagonal settings of this structure can be obtained with the option --hex.

\[ \begin{array}{ccc} \mathbf{a_{1}}&=&\frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+\frac{1}{3}c \,\mathbf{\hat{z}}\\\mathbf{a_{2}}&=&\frac{1}{\sqrt{3}}a \,\mathbf{\hat{y}}+\frac{1}{3}c \,\mathbf{\hat{z}}\\\mathbf{a_{3}}&=&- \frac{1}{2}a \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+\frac{1}{3}c \,\mathbf{\hat{z}} \end{array}\]

Basis vectors

Lattice coordinates Cartesian coordinates Wyckoff position Atom type
$\mathbf{B_{1}}$ = $0$ = $0$ (1a) C I
$\mathbf{B_{2}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{2}c \,\mathbf{\hat{z}}$ (1b) Ca I
$\mathbf{B_{3}}$ = $y_{3} \, \mathbf{a}_{2}- y_{3} \, \mathbf{a}_{3}$ = $\frac{1}{2}a y_{3} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a y_{3} \,\mathbf{\hat{y}}$ (3d) C II
$\mathbf{B_{4}}$ = $- y_{3} \, \mathbf{a}_{1}+y_{3} \, \mathbf{a}_{3}$ = $- a y_{3} \,\mathbf{\hat{x}}$ (3d) C II
$\mathbf{B_{5}}$ = $y_{3} \, \mathbf{a}_{1}- y_{3} \, \mathbf{a}_{2}$ = $\frac{1}{2}a y_{3} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a y_{3} \,\mathbf{\hat{y}}$ (3d) C II
$\mathbf{B_{6}}$ = $y_{4} \, \mathbf{a}_{2}- y_{4} \, \mathbf{a}_{3}$ = $\frac{1}{2}a y_{4} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a y_{4} \,\mathbf{\hat{y}}$ (3d) O I
$\mathbf{B_{7}}$ = $- y_{4} \, \mathbf{a}_{1}+y_{4} \, \mathbf{a}_{3}$ = $- a y_{4} \,\mathbf{\hat{x}}$ (3d) O I
$\mathbf{B_{8}}$ = $y_{4} \, \mathbf{a}_{1}- y_{4} \, \mathbf{a}_{2}$ = $\frac{1}{2}a y_{4} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a y_{4} \,\mathbf{\hat{y}}$ (3d) O I
$\mathbf{B_{9}}$ = $y_{5} \, \mathbf{a}_{2}- y_{5} \, \mathbf{a}_{3}$ = $\frac{1}{2}a y_{5} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{2}a y_{5} \,\mathbf{\hat{y}}$ (3d) O II
$\mathbf{B_{10}}$ = $- y_{5} \, \mathbf{a}_{1}+y_{5} \, \mathbf{a}_{3}$ = $- a y_{5} \,\mathbf{\hat{x}}$ (3d) O II
$\mathbf{B_{11}}$ = $y_{5} \, \mathbf{a}_{1}- y_{5} \, \mathbf{a}_{2}$ = $\frac{1}{2}a y_{5} \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{2}a y_{5} \,\mathbf{\hat{y}}$ (3d) O II
$\mathbf{B_{12}}$ = $\frac{1}{2} \, \mathbf{a}_{1}+y_{6} \, \mathbf{a}_{2}- y_{6} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \left(2 y_{6} + 1\right) \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{12}a \left(6 y_{6} - 1\right) \,\mathbf{\hat{y}}+\frac{1}{6}c \,\mathbf{\hat{z}}$ (3e) Mg I
$\mathbf{B_{13}}$ = $- y_{6} \, \mathbf{a}_{1}+\frac{1}{2} \, \mathbf{a}_{2}+y_{6} \, \mathbf{a}_{3}$ = $- a y_{6} \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \,\mathbf{\hat{y}}+\frac{1}{6}c \,\mathbf{\hat{z}}$ (3e) Mg I
$\mathbf{B_{14}}$ = $y_{6} \, \mathbf{a}_{1}- y_{6} \, \mathbf{a}_{2}+\frac{1}{2} \, \mathbf{a}_{3}$ = $\frac{1}{4}a \left(2 y_{6} - 1\right) \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{12}a \left(6 y_{6} + 1\right) \,\mathbf{\hat{y}}+\frac{1}{6}c \,\mathbf{\hat{z}}$ (3e) Mg I
$\mathbf{B_{15}}$ = $x_{7} \, \mathbf{a}_{1}+y_{7} \, \mathbf{a}_{2}+z_{7} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \left(x_{7} - z_{7}\right) \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \left(x_{7} - 2 y_{7} + z_{7}\right) \,\mathbf{\hat{y}}+\frac{1}{3}c \left(x_{7} + y_{7} + z_{7}\right) \,\mathbf{\hat{z}}$ (6f) O III
$\mathbf{B_{16}}$ = $z_{7} \, \mathbf{a}_{1}+x_{7} \, \mathbf{a}_{2}+y_{7} \, \mathbf{a}_{3}$ = $- \frac{1}{2}a \left(y_{7} - z_{7}\right) \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \left(2 x_{7} - y_{7} - z_{7}\right) \,\mathbf{\hat{y}}+\frac{1}{3}c \left(x_{7} + y_{7} + z_{7}\right) \,\mathbf{\hat{z}}$ (6f) O III
$\mathbf{B_{17}}$ = $y_{7} \, \mathbf{a}_{1}+z_{7} \, \mathbf{a}_{2}+x_{7} \, \mathbf{a}_{3}$ = $- \frac{1}{2}a \left(x_{7} - y_{7}\right) \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \left(x_{7} + y_{7} - 2 z_{7}\right) \,\mathbf{\hat{y}}+\frac{1}{3}c \left(x_{7} + y_{7} + z_{7}\right) \,\mathbf{\hat{z}}$ (6f) O III
$\mathbf{B_{18}}$ = $- z_{7} \, \mathbf{a}_{1}- y_{7} \, \mathbf{a}_{2}- x_{7} \, \mathbf{a}_{3}$ = $\frac{1}{2}a \left(x_{7} - z_{7}\right) \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \left(x_{7} - 2 y_{7} + z_{7}\right) \,\mathbf{\hat{y}}- \frac{1}{3}c \left(x_{7} + y_{7} + z_{7}\right) \,\mathbf{\hat{z}}$ (6f) O III
$\mathbf{B_{19}}$ = $- y_{7} \, \mathbf{a}_{1}- x_{7} \, \mathbf{a}_{2}- z_{7} \, \mathbf{a}_{3}$ = $- \frac{1}{2}a \left(y_{7} - z_{7}\right) \,\mathbf{\hat{x}}- \frac{\sqrt{3}}{6}a \left(2 x_{7} - y_{7} - z_{7}\right) \,\mathbf{\hat{y}}- \frac{1}{3}c \left(x_{7} + y_{7} + z_{7}\right) \,\mathbf{\hat{z}}$ (6f) O III
$\mathbf{B_{20}}$ = $- x_{7} \, \mathbf{a}_{1}- z_{7} \, \mathbf{a}_{2}- y_{7} \, \mathbf{a}_{3}$ = $- \frac{1}{2}a \left(x_{7} - y_{7}\right) \,\mathbf{\hat{x}}+\frac{\sqrt{3}}{6}a \left(x_{7} + y_{7} - 2 z_{7}\right) \,\mathbf{\hat{y}}- \frac{1}{3}c \left(x_{7} + y_{7} + z_{7}\right) \,\mathbf{\hat{z}}$ (6f) O III

References

  • W. A. Dollase and R. J. Reeder, Crystal structure refinement of huntite, CaMg$_{3}$(CO$_{3}$)$_{4}$, with X-ray powder data, Am. Mineral. 71, 163–166 (1986).

Prototype Generator

aflow --proto=A4BC3D12_hR20_155_ad_b_e_2df --params=$a,c/a,y_{3},y_{4},y_{5},y_{6},x_{7},y_{7},z_{7}$

Species:

Running:

Output: